Optimal. Leaf size=274 \[ \frac {12 a^{5/4} \sqrt [4]{b} \sqrt {x} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 \sqrt {a x+b x^3}}-\frac {24 a^{5/4} \sqrt [4]{b} \sqrt {x} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 \sqrt {a x+b x^3}}+\frac {12}{5} b x \sqrt {a x+b x^3}-\frac {2 \left (a x+b x^3\right )^{3/2}}{x^2}+\frac {24 a \sqrt {b} x \left (a+b x^2\right )}{5 \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {a x+b x^3}} \]
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Rubi [A] time = 0.23, antiderivative size = 274, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.412, Rules used = {2020, 2004, 2032, 329, 305, 220, 1196} \[ \frac {12 a^{5/4} \sqrt [4]{b} \sqrt {x} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 \sqrt {a x+b x^3}}-\frac {24 a^{5/4} \sqrt [4]{b} \sqrt {x} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 \sqrt {a x+b x^3}}-\frac {2 \left (a x+b x^3\right )^{3/2}}{x^2}+\frac {12}{5} b x \sqrt {a x+b x^3}+\frac {24 a \sqrt {b} x \left (a+b x^2\right )}{5 \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {a x+b x^3}} \]
Antiderivative was successfully verified.
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Rule 220
Rule 305
Rule 329
Rule 1196
Rule 2004
Rule 2020
Rule 2032
Rubi steps
\begin {align*} \int \frac {\left (a x+b x^3\right )^{3/2}}{x^3} \, dx &=-\frac {2 \left (a x+b x^3\right )^{3/2}}{x^2}+(6 b) \int \sqrt {a x+b x^3} \, dx\\ &=\frac {12}{5} b x \sqrt {a x+b x^3}-\frac {2 \left (a x+b x^3\right )^{3/2}}{x^2}+\frac {1}{5} (12 a b) \int \frac {x}{\sqrt {a x+b x^3}} \, dx\\ &=\frac {12}{5} b x \sqrt {a x+b x^3}-\frac {2 \left (a x+b x^3\right )^{3/2}}{x^2}+\frac {\left (12 a b \sqrt {x} \sqrt {a+b x^2}\right ) \int \frac {\sqrt {x}}{\sqrt {a+b x^2}} \, dx}{5 \sqrt {a x+b x^3}}\\ &=\frac {12}{5} b x \sqrt {a x+b x^3}-\frac {2 \left (a x+b x^3\right )^{3/2}}{x^2}+\frac {\left (24 a b \sqrt {x} \sqrt {a+b x^2}\right ) \operatorname {Subst}\left (\int \frac {x^2}{\sqrt {a+b x^4}} \, dx,x,\sqrt {x}\right )}{5 \sqrt {a x+b x^3}}\\ &=\frac {12}{5} b x \sqrt {a x+b x^3}-\frac {2 \left (a x+b x^3\right )^{3/2}}{x^2}+\frac {\left (24 a^{3/2} \sqrt {b} \sqrt {x} \sqrt {a+b x^2}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {a+b x^4}} \, dx,x,\sqrt {x}\right )}{5 \sqrt {a x+b x^3}}-\frac {\left (24 a^{3/2} \sqrt {b} \sqrt {x} \sqrt {a+b x^2}\right ) \operatorname {Subst}\left (\int \frac {1-\frac {\sqrt {b} x^2}{\sqrt {a}}}{\sqrt {a+b x^4}} \, dx,x,\sqrt {x}\right )}{5 \sqrt {a x+b x^3}}\\ &=\frac {24 a \sqrt {b} x \left (a+b x^2\right )}{5 \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {a x+b x^3}}+\frac {12}{5} b x \sqrt {a x+b x^3}-\frac {2 \left (a x+b x^3\right )^{3/2}}{x^2}-\frac {24 a^{5/4} \sqrt [4]{b} \sqrt {x} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 \sqrt {a x+b x^3}}+\frac {12 a^{5/4} \sqrt [4]{b} \sqrt {x} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 \sqrt {a x+b x^3}}\\ \end {align*}
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Mathematica [C] time = 0.02, size = 52, normalized size = 0.19 \[ -\frac {2 a \sqrt {x \left (a+b x^2\right )} \, _2F_1\left (-\frac {3}{2},-\frac {1}{4};\frac {3}{4};-\frac {b x^2}{a}\right )}{x \sqrt {\frac {b x^2}{a}+1}} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.69, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\sqrt {b x^{3} + a x} {\left (b x^{2} + a\right )}}{x^{2}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b x^{3} + a x\right )}^{\frac {3}{2}}}{x^{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.07, size = 194, normalized size = 0.71 \[ \frac {2 \sqrt {b \,x^{3}+a x}\, b x}{5}-\frac {2 \left (b \,x^{2}+a \right ) a}{\sqrt {\left (b \,x^{2}+a \right ) x}}+\frac {12 \sqrt {-a b}\, \sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {b x}{\sqrt {-a b}}}\, \left (-\frac {2 \sqrt {-a b}\, \EllipticE \left (\sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{b}+\frac {\sqrt {-a b}\, \EllipticF \left (\sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{b}\right ) a}{5 \sqrt {b \,x^{3}+a x}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b x^{3} + a x\right )}^{\frac {3}{2}}}{x^{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (b\,x^3+a\,x\right )}^{3/2}}{x^3} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (x \left (a + b x^{2}\right )\right )^{\frac {3}{2}}}{x^{3}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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